What is expand Dx[(x^2-3x+2)(2x^3+1)] ?

The solution to expand Dx[(x^2-3x+2)(2x^3+1)] is 2Dx^6+Dx^3-6Dx^5-3Dx^2+4Dx^4+2Dx

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expand Dx[(x^2-3x+2)(2x^3+1)]

expand

D x [(x^{2} - 3 x + 2) (2 x^{3} + 1)]

2 D x^{6} + D x^{3} - 6 D x^{5} - 3 D x^{2} + 4 D x^{4} + 2 D x

Solution steps

D x ((x^{2} - 3 x + 2) (2 x^{3} + 1))

Remove parentheses:

(a) = a

= D x (x^{2} - 3 x + 2) (2 x^{3} + 1)

Expand

(x^{2} - 3 x + 2) (2 x^{3} + 1) : 2 x^{5} + x^{2} - 6 x^{4} - 3 x + 4 x^{3} + 2

= D x (2 x^{5} + x^{2} - 6 x^{4} - 3 x + 4 x^{3} + 2)

Expand

D x (2 x^{5} + x^{2} - 6 x^{4} - 3 x + 4 x^{3} + 2) : 2 D x^{6} + D x^{3} - 6 D x^{5} - 3 D x^{2} + 4 D x^{4} + 2 D x

= 2 D x^{6} + D x^{3} - 6 D x^{5} - 3 D x^{2} + 4 D x^{4} + 2 D x

\frac{3}{( 6 + x ) ^{3}}

\frac{1}{x ( x - 6 )}

(1 - sin (x)) (1 + csc (x))

(2 + 3)^{4}

(x - 2) ln (x)

What is expand Dx[(x^2-3x+2)(2x^3+1)] ?
The solution to expand Dx[(x^2-3x+2)(2x^3+1)] is 2Dx^6+Dx^3-6Dx^5-3Dx^2+4Dx^4+2Dx