What is expand ((x+3)(x-2))/((x+2)(x-1)) ?

The solution to expand ((x+3)(x-2))/((x+2)(x-1)) is (x^2+x-6)/(x^2+x-2)

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expand ((x+3)(x-2))/((x+2)(x-1))

expand

\frac{( x + 3 ) ( x - 2 )}{( x + 2 ) ( x - 1 )}

\frac{x ^{2} + x - 6}{x ^{2} + x - 2}

Solution steps

\frac{( x + 3 ) ( x - 2 )}{( x + 2 ) ( x - 1 )}

Expand

(x + 2) (x - 1) : x^{2} + x - 2

= \frac{( x + 3 ) ( x - 2 )}{x ^{2} + x - 2}

Expand

(x + 3) (x - 2) : x^{2} + x - 6

= \frac{x ^{2} + x - 6}{x ^{2} + x - 2}

(e^{i x} - e^{- i x})^{2}

(x + 2) (2 - \frac{3}{x})^{6}

\frac{\partial}{\partial y} ((z) (4 x^{2} y + 3 y - 5))

(x + y - 1) d x - (2 x - y + 1) d y

\frac{x ^{2} + 2 x}{( x + 1 ) ( x ^{2} + 4 )}

What is expand ((x+3)(x-2))/((x+2)(x-1)) ?
The solution to expand ((x+3)(x-2))/((x+2)(x-1)) is (x^2+x-6)/(x^2+x-2)