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Popular >

simplify (3-4i)^4

Solution

simplify

(3 - 4 i)^{4}

Solution

- 527 + 336 i

Solution steps

(3 - 4 i)^{4}

Apply binomial theorem:

(a + b)^{n} = i = 0 \sum n (i n) a^{(n - i)} b^{i}

a = 3, b = - 4 i

= i = 0 \sum 4 (i 4) \cdot 3^{(4 - i)} (- 4 i)^{i}

Expand summation

= \frac{4 !}{0 ! ( 4 - 0 ) !} \cdot 3^{4} (- 4 i)^{0} + \frac{4 !}{1 ! ( 4 - 1 ) !} \cdot 3^{3} (- 4 i)^{1} + \frac{4 !}{2 ! ( 4 - 2 ) !} \cdot 3^{2} (- 4 i)^{2} + \frac{4 !}{3 ! ( 4 - 3 ) !} \cdot 3^{1} (- 4 i)^{3} + \frac{4 !}{4 ! ( 4 - 4 ) !} \cdot 3^{0} (- 4 i)^{4}

Simplify

\frac{4 !}{0 ! ( 4 - 0 ) !} \cdot 3^{4} (- 4 i)^{0} : 81

Simplify

\frac{4 !}{1 ! ( 4 - 1 ) !} \cdot 3^{3} (- 4 i)^{1} : - 432 i

Simplify

\frac{4 !}{2 ! ( 4 - 2 ) !} \cdot 3^{2} (- 4 i)^{2} : 864 i^{2}

Simplify

\frac{4 !}{3 ! ( 4 - 3 ) !} \cdot 3^{1} (- 4 i)^{3} : - 768 i^{3}

Simplify

\frac{4 !}{4 ! ( 4 - 4 ) !} \cdot 3^{0} (- 4 i)^{4} : 256 i^{4}

= 81 - 432 i + 864 i^{2} - 768 i^{3} + 256 i^{4}

Simplify

81 - 432 i + 864 i^{2} - 768 i^{3} + 256 i^{4} : 336 i - 527

= 336 i - 527

Rewrite in standard complex form:

- 527 + 336 i

= - 527 + 336 i

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Frequently Asked Questions (FAQ)

What is (3-4i)^4 ?
The solution to (3-4i)^4 is -527+336i