What is expand ((x-3)^2)/(4(x-1)) ?

The solution to expand ((x-3)^2)/(4(x-1)) is (x^2-6x+9)/(4x-4)

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expand ((x-3)^2)/(4(x-1))

expand

\frac{( x - 3 ) ^{2}}{4 ( x - 1 )}

\frac{x ^{2} - 6 x + 9}{4 x - 4}

Solution steps

\frac{( x - 3 ) ^{2}}{4 ( x - 1 )}

(x - 3)^{2} = x^{2} - 6 x + 9

= \frac{x ^{2} - 6 x + 9}{4 ( x - 1 )}

Expand

4 (x - 1) : 4 x - 4

= \frac{x ^{2} - 6 x + 9}{4 x - 4}

(1 + x - 1 - x)^{2}

(sec (x) + csc (x)) (cos (x) - sin (x))

(- 7 sin (x) + 7 sin (7 x))^{2}

\frac{1}{( x - a ) ( x - b )}

(5 x + y)^{6}

What is expand ((x-3)^2)/(4(x-1)) ?
The solution to expand ((x-3)^2)/(4(x-1)) is (x^2-6x+9)/(4x-4)