What is (1+x+(x^2)/2)(x-(x^2)/2+(x^3)/3) ?

The solution to (1+x+(x^2)/2)(x-(x^2)/2+(x^3)/3) is ((2+2x+x^2)(6x-3x^2+2x^3))/(12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (1+x+(x^2)/2)(x-(x^2)/2+(x^3)/3)

simplify

(1 + x + \frac{x ^{2}}{2}) (x - \frac{x ^{2}}{2} + \frac{x ^{3}}{3})

\frac{( 2 + 2 x + x ^{2} ) ( 6 x - 3 x ^{2} + 2 x ^{3} )}{12}

Solution steps

(1 + x + \frac{x ^{2}}{2}) (x - \frac{x ^{2}}{2} + \frac{x ^{3}}{3})

Simplify

1 + x + \frac{x ^{2}}{2} : \frac{2 + 2 x + x ^{2}}{2}

= \frac{2 + 2 x + x ^{2}}{2} (x - \frac{x ^{2}}{2} + \frac{x ^{3}}{3})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 + 2 x + x ^{2} ) ( x - \frac{x ^{2}}{2} + \frac{x ^{3}}{3} )}{2}

Simplify

(2 + 2 x + x^{2}) (x - \frac{x ^{2}}{2} + \frac{x ^{3}}{3}) : \frac{( 2 + 2 x + x ^{2} ) ( x \cdot 6 - x ^{2} \cdot 3 + x ^{3} \cdot 2 )}{6}

= \frac{\frac{( 2 + 2 x + x ^{2} ) ( x \cdot 6 - x ^{2} \cdot 3 + x ^{3} \cdot 2 )}{6}}{2}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 2 + 2 x + x ^{2} ) ( x \cdot 6 - x ^{2} \cdot 3 + x ^{3} \cdot 2 )}{6 \cdot 2}

Multiply the numbers:

6 \cdot 2 = 12

= \frac{( 2 + 2 x + x ^{2} ) ( x \cdot 6 - x ^{2} \cdot 3 + x ^{3} \cdot 2 )}{12}

= \frac{( 2 + 2 x + x ^{2} ) ( 6 x - 3 x ^{2} + 2 x ^{3} )}{12}

lo g_{10} (3) (x + 1)

A (- 5, 4) B (3, - 2)

(25 - 3) (27 - 2)

(5 sin (x) + 5 cos (x))^{2}

(1 + 5 z i)^{2}

What is (1+x+(x^2)/2)(x-(x^2)/2+(x^3)/3) ?
The solution to (1+x+(x^2)/2)(x-(x^2)/2+(x^3)/3) is ((2+2x+x^2)(6x-3x^2+2x^3))/(12)