What is expand ((x+1)(x+4)(x-2)(x-5))/((x+2)(x-1)) ?

The solution to expand ((x+1)(x+4)(x-2)(x-5))/((x+2)(x-1)) is (x^4-2x^3-21x^2+22x+40)/(x^2+x-2)

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expand ((x+1)(x+4)(x-2)(x-5))/((x+2)(x-1))

expand

\frac{( x + 1 ) ( x + 4 ) ( x - 2 ) ( x - 5 )}{( x + 2 ) ( x - 1 )}

\frac{x ^{4} - 2 x ^{3} - 21 x ^{2} + 22 x + 40}{x ^{2} + x - 2}

Solution steps

\frac{( x + 1 ) ( x + 4 ) ( x - 2 ) ( x - 5 )}{( x + 2 ) ( x - 1 )}

Expand

(x + 2) (x - 1) : x^{2} + x - 2

= \frac{( x + 1 ) ( x + 4 ) ( x - 2 ) ( x - 5 )}{x ^{2} + x - 2}

Expand

(x + 1) (x + 4) (x - 2) (x - 5) : x^{4} - 2 x^{3} - 21 x^{2} + 22 x + 40

= \frac{x ^{4} - 2 x ^{3} - 21 x ^{2} + 22 x + 40}{x ^{2} + x - 2}

\frac{9}{( 4 + x ) ^{3}}

\frac{d}{d x} ((3 x - 1) (2 x - 5)) - \frac{4 x ^{2}}{2 - 3 x}

2 x^{3} δ (x - 3)

\frac{( 2 x + 3 ) ^{2} ( x - 2 ) ^{5}}{x ^{3} ( x - 5 ) ^{2}}

\frac{1}{x ( x ^{2} + 4 )}

What is expand ((x+1)(x+4)(x-2)(x-5))/((x+2)(x-1)) ?
The solution to expand ((x+1)(x+4)(x-2)(x-5))/((x+2)(x-1)) is (x^4-2x^3-21x^2+22x+40)/(x^2+x-2)