What is (\partial)/(\partial t)((x)(s+t)) ?

The answer to (\partial)/(\partial t)((x)(s+t)) is x

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(\partial)/(\partial t)((x)(s+t))

\frac{\partial}{\partial t} ((x) (s + t))

x

Solution steps

\frac{\partial}{\partial t} ((x) (s + t))

Treat

x, s

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{\partial}{\partial t} (s + t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (\frac{\partial}{\partial t} (s) + \frac{\partial}{\partial t} (t))

\frac{\partial}{\partial t} (s) = 0

\frac{\partial}{\partial t} (t) = 1

= x (0 + 1)

Simplify

= x

(1 + x) d y

(x + i y)^{4}

\frac{1}{( 1 - x ^{2} ) ^{2}}

(x - 2) (x + 3) (x - \frac{1}{2})

What is (\partial)/(\partial t)((x)(s+t)) ?
The answer to (\partial)/(\partial t)((x)(s+t)) is x