What is expand (1-1/4 x^2)^2 ?

The solution to expand (1-1/4 x^2)^2 is (16-8x^2+x^4)/(16)

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expand (1-1/4 x^2)^2

expand

(1 - \frac{1}{4} x^{2})^{2}

\frac{16 - 8 x ^{2} + x ^{4}}{16}

Solution steps

(1 - \frac{1}{4} x^{2})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(1 - \frac{1}{4} x^{2})^{2} = 1^{2} - 2 \cdot 1 \cdot \frac{1}{4} x^{2} + (\frac{1}{4} x^{2})^{2}

= 1^{2} - 2 \cdot 1 \cdot \frac{1}{4} x^{2} + (\frac{1}{4} x^{2})^{2}

Simplify

1^{2} - 2 \cdot 1 \cdot \frac{1}{4} x^{2} + (\frac{1}{4} x^{2})^{2} : \frac{16 - 8 x ^{2} + x ^{4}}{16}

= \frac{16 - 8 x ^{2} + x ^{4}}{16}

(i + 1)^{11}

\frac{3}{2} (x - \frac{π}{6})

\frac{2 x}{( 1 + x ^{2} ) ^{2}}

(2 x - 3) (2 x + 3)

x (x^{3} - x y^{2} + 2 y^{3}) d y - y (x^{3} + 2 y^{3}) d x

What is expand (1-1/4 x^2)^2 ?
The solution to expand (1-1/4 x^2)^2 is (16-8x^2+x^4)/(16)