What is expand ((x+2)(x-4))/((x-2)(x-6)) ?

The solution to expand ((x+2)(x-4))/((x-2)(x-6)) is (x^2-2x-8)/(x^2-8x+12)

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expand ((x+2)(x-4))/((x-2)(x-6))

expand

\frac{( x + 2 ) ( x - 4 )}{( x - 2 ) ( x - 6 )}

\frac{x ^{2} - 2 x - 8}{x ^{2} - 8 x + 12}

Solution steps

\frac{( x + 2 ) ( x - 4 )}{( x - 2 ) ( x - 6 )}

Expand

(x - 2) (x - 6) : x^{2} - 8 x + 12

= \frac{( x + 2 ) ( x - 4 )}{x ^{2} - 8 x + 12}

Expand

(x + 2) (x - 4) : x^{2} - 2 x - 8

= \frac{x ^{2} - 2 x - 8}{x ^{2} - 8 x + 12}

(a^{\frac{1}{2}} + b^{\frac{1}{2}})^{2}

(0.5 \cdot \frac{1}{3} + \frac{1}{5}) \cdot 1.2

e^{k t} (cosh (2 k t) - H (t - a) (t - b))

sin^{2} (y) + (cos (y) - tan (y)) (cos (y) + tan (y))

\frac{1}{2} (cosh (2 x) - 1)

What is expand ((x+2)(x-4))/((x-2)(x-6)) ?
The solution to expand ((x+2)(x-4))/((x-2)(x-6)) is (x^2-2x-8)/(x^2-8x+12)