What is factor (a^2+2a)^2-64 ?

The solution to factor (a^2+2a)^2-64 is (a^2+2a+8)(a-2)(a+4)

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factor (a^2+2a)^2-64

factor

(a^{2} + 2 a)^{2} - 64

(a^{2} + 2 a + 8) (a - 2) (a + 4)

Solution steps

(a^{2} + 2 a)^{2} - 64

Factor the number:

64 = 8^{2}

= (a^{2} + 2 a)^{2} - 8^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(a^{2} + 2 a)^{2} - 8^{2} = ((a^{2} + 2 a) + 8) ((a^{2} + 2 a) - 8)

= ((a^{2} + 2 a) + 8) ((a^{2} + 2 a) - 8)

Apply rule:

(a) = a

(a^{2} + 2 a) = a^{2} + 2 a

= (a^{2} + 2 a + 8) (a^{2} + 2 a - 8)

Factor

a^{2} + 2 a - 8 : (a - 2) (a + 4)

= (a^{2} + 2 a + 8) (a - 2) (a + 4)

∣ 3 x + x ∣ = 4

∣ x + 3 ∣ = 5

- 3 = (x - 2)^{2} - 7

21

2 x z - 6 x y + 2 yz - 6 y^{2}

What is factor (a^2+2a)^2-64 ?
The solution to factor (a^2+2a)^2-64 is (a^2+2a+8)(a-2)(a+4)