What is expand (x^2-5x+16)/((2x+1)(x-2)^2) ?

The solution to expand (x^2-5x+16)/((2x+1)(x-2)^2) is (x^2-5x+16)/(2x^3-7x^2+4x+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x^2-5x+16)/((2x+1)(x-2)^2)

expand

\frac{x ^{2} - 5 x + 16}{( 2 x + 1 ) ( x - 2 ) ^{2}}

\frac{x ^{2} - 5 x + 16}{2 x ^{3} - 7 x ^{2} + 4 x + 4}

Solution steps

\frac{x ^{2} - 5 x + 16}{( 2 x + 1 ) ( x - 2 ) ^{2}}

(x - 2)^{2} = x^{2} - 4 x + 4

= \frac{x ^{2} - 5 x + 16}{( 2 x + 1 ) ( x ^{2} - 4 x + 4 )}

Expand

(2 x + 1) (x^{2} - 4 x + 4) : 2 x^{3} - 7 x^{2} + 4 x + 4

= \frac{x ^{2} - 5 x + 16}{2 x ^{3} - 7 x ^{2} + 4 x + 4}

- \frac{8 ( - 3 x ^{2} - 4 )}{( x ^{2} - 4 ) ^{3}}

- 6 y l e f t (5 y^{2} - 4 y + 2)

\frac{x ^{2} + 1}{( x ^{3} - 5 x ^{2} - 6 x ) ( x ^{2} + x + 9 )}

(- 3 - i)^{5}

\frac{8 x ^{2} + 13}{( x ^{2} + 1 ) ( x + 1 )}

What is expand (x^2-5x+16)/((2x+1)(x-2)^2) ?
The solution to expand (x^2-5x+16)/((2x+1)(x-2)^2) is (x^2-5x+16)/(2x^3-7x^2+4x+4)