What is expand P(0,-3)yQ(-1,7) ?

The solution to expand P(0,-3)yQ(-1,7) is 0*(-1*7,)PyQ,-3(-1*7,)PyQ

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expand P(0,-3)yQ(-1,7)

expand

P (0, - 3) y Q (- 1, 7)

0 \cdot (- 1 \cdot 7,) P y Q, - 3 (- 1 \cdot 7,) P y Q

Solution steps

P (0, - 3) y Q (- 1, 7)

= (0, - 3) (- 1 \cdot 7,) P y Q

Apply the distributive law:

a (b - c) = ab - a c

a = P y Q (- 1, 7), b = 0,, c = 3

= P y Q (- 1, 7) \cdot 0, - P y Q (- 1, 7) \cdot 3

= 0 \cdot (- 1 \cdot 7,) P y Q, - 3 (- 1 \cdot 7,) P y Q

\frac{1}{x ( x + 1 ) ( x + 2 )}

\frac{20}{x ( x - 5 )}

\frac{d ^{2}}{d x ^{2}} ((y) (x^{3} + y^{3}))

\frac{29 ( 400 3 - 369 )}{1250}

What is expand P(0,-3)yQ(-1,7) ?
The solution to expand P(0,-3)yQ(-1,7) is 0*(-1*7,)PyQ,-3(-1*7,)PyQ