What is expand log_{4}(2x^2)(x+1) ?

The solution to expand log_{4}(2x^2)(x+1) is (x(2log_{2}(x)+1)+2log_{2}(x)+1)/2

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expand log_{4}(2x^2)(x+1)

expand

lo g_{4} (2 x^{2}) (x + 1)

\frac{x ( 2 lo g _{2} ( x ) + 1 ) + 2 lo g _{2} ( x ) + 1}{2}

Solution steps

lo g_{4} (2 x^{2}) (x + 1)

Apply the distributive law:

a (b + c) = ab + a c

lo g_{4} (2 x^{2}) (x + 1) = lo g_{4} (2 x^{2}) x + lo g_{4} (2 x^{2}) \cdot 1

= lo g_{4} (2 x^{2}) x + lo g_{4} (2 x^{2}) \cdot 1

Simplify

lo g_{4} (2 x^{2}) x + lo g_{4} (2 x^{2}) \cdot 1 : \frac{x ( 2 lo g _{2} ( x ) + 1 ) + 2 lo g _{2} ( x ) + 1}{2}

= \frac{x ( 2 lo g _{2} ( x ) + 1 ) + 2 lo g _{2} ( x ) + 1}{2}

(7 - x)^{2}

\frac{16 ( 3 - 5 )}{5}

(a - 2) l e f t (a + 12)

(1 - \frac{1}{x})^{20}

(1 + x)^{3}

What is expand log_{4}(2x^2)(x+1) ?
The solution to expand log_{4}(2x^2)(x+1) is (x(2log_{2}(x)+1)+2log_{2}(x)+1)/2