What are the solutions to the equation b^2-6b+5=-4 ?

The solutions to the equation b^2-6b+5=-4 are b=3

Find the zeros of b^2-6b+5=-4

The zeros of b^2-6b+5=-4 are b=3

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b^{2} - 6 b + 5 = - 4

b = 3

Solution steps

b^{2} - 6 b + 5 = - 4

Move

4

to the left side

b^{2} - 6 b + 9 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 9 = 0

b_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 1}

b = \frac{- ( - 6 )}{2 \cdot 1}

\frac{- ( - 6 )}{2 \cdot 1} = 3

b = 3

The solution to the quadratic equation is:

b = 3

- 12 y^{2} - 36 y = 0

x^{2} - 18 = 0

(- \frac{2}{5})^{5}

∣ 7 x + 2 ∣ \leq 4

5 x + 7 < 6 x + 15 \leq 3 x + 21

What are the solutions to the equation b^2-6b+5=-4 ?
The solutions to the equation b^2-6b+5=-4 are b=3
Find the zeros of b^2-6b+5=-4
The zeros of b^2-6b+5=-4 are b=3