What is expand 2^xln(2)(x+1) ?

The solution to expand 2^xln(2)(x+1) is ln(2)*2^xx+ln(2)*2^x

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expand 2^xln(2)(x+1)

expand

2^{x} ln (2) (x + 1)

ln (2) \cdot 2^{x} x + ln (2) \cdot 2^{x}

Solution steps

2^{x} ln (2) (x + 1)

= ln (2) \cdot 2^{x} (x + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = 2^{x} ln (2), b = x, c = 1

= 2^{x} ln (2) x + 2^{x} ln (2) \cdot 1

= ln (2) \cdot 2^{x} x + 1 \cdot ln (2) \cdot 2^{x}

Multiply:

1 \cdot ln (2) = ln (2)

= ln (2) \cdot 2^{x} x + ln (2) \cdot 2^{x}

\frac{x}{( x + 1 ) ( x - 4 )}

(x + 5)^{2} d x

\frac{s + 3}{( s + 1 ) ( s + 2 )}

(x^{2} + e^{x}) (2 x e^{x})

\frac{π ( 3 - 3 )}{3}

What is expand 2^xln(2)(x+1) ?
The solution to expand 2^xln(2)(x+1) is ln(2)*2^xx+ln(2)*2^x