What is expand (-x^2-2x+3)/((x^2+3)^2) ?

The solution to expand (-x^2-2x+3)/((x^2+3)^2) is (-x^2-2x+3)/(x^4+6x^2+9)

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expand (-x^2-2x+3)/((x^2+3)^2)

expand

\frac{- x ^{2} - 2 x + 3}{( x ^{2} + 3 ) ^{2}}

\frac{- x ^{2} - 2 x + 3}{x ^{4} + 6 x ^{2} + 9}

Solution steps

\frac{- x ^{2} - 2 x + 3}{( x ^{2} + 3 ) ^{2}}

(x^{2} + 3)^{2} = x^{4} + 6 x^{2} + 9

= \frac{- x ^{2} - 2 x + 3}{x ^{4} + 6 x ^{2} + 9}

(2 x^{3} - \frac{1}{x})^{12}

(t cos (t)) (cos (t) - t sin (t))

(3 z + 5 i)^{2}

(- 1 + i)^{11}

(sin (x) + cos (x))^{2}

What is expand (-x^2-2x+3)/((x^2+3)^2) ?
The solution to expand (-x^2-2x+3)/((x^2+3)^2) is (-x^2-2x+3)/(x^4+6x^2+9)