What is expand (2x+1/3)^3 ?

The solution to expand (2x+1/3)^3 is (216x^3+108x^2+18x+1)/(27)

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expand (2x+1/3)^3

expand

(2 x + \frac{1}{3})^{3}

\frac{216 x ^{3} + 108 x ^{2} + 18 x + 1}{27}

Solution steps

(2 x + \frac{1}{3})^{3}

Apply Perfect Cube Formula:

(a + b)^{3} = a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}

(2 x + \frac{1}{3})^{3} = (2 x)^{3} + 3 (2 x)^{2} \frac{1}{3} + 3 \cdot 2 x (\frac{1}{3})^{2} + (\frac{1}{3})^{3}

= (2 x)^{3} + 3 (2 x)^{2} \frac{1}{3} + 3 \cdot 2 x (\frac{1}{3})^{2} + (\frac{1}{3})^{3}

Simplify

(2 x)^{3} + 3 (2 x)^{2} \frac{1}{3} + 3 \cdot 2 x (\frac{1}{3})^{2} + (\frac{1}{3})^{3} : \frac{216 x ^{3} + 108 x ^{2} + 18 x + 1}{27}

= \frac{216 x ^{3} + 108 x ^{2} + 18 x + 1}{27}

(cos^{2} (x) + sec^{2} (x)) (cos^{2} (x) - 2)

\frac{( x ^{2} - 1 ) ^{4}}{4}

\frac{1}{x ( x - a ) ^{2}}

\frac{2 ( 3 x + 1 ) ( x ^{3} + 2 x - 7 )}{x ^{6} - 2 x + 7}

(- 1)^{n} (1 - \frac{1}{n})

What is expand (2x+1/3)^3 ?
The solution to expand (2x+1/3)^3 is (216x^3+108x^2+18x+1)/(27)