What is expand (6z)/((z-3)(z+1)) ?

The solution to expand (6z)/((z-3)(z+1)) is (6z)/(z^2-2z-3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (6z)/((z-3)(z+1))

expand

\frac{6 z}{( z - 3 ) ( z + 1 )}

\frac{6 z}{z ^{2} - 2 z - 3}

Solution steps

\frac{6 z}{( z - 3 ) ( z + 1 )}

Expand

(z - 3) (z + 1) : z^{2} - 2 z - 3

= \frac{6 z}{z ^{2} - 2 z - 3}

\frac{1}{( x - 5 ) ^{2}}

(5 x - 2) (5 x + 2)

(x + \frac{3}{2})^{2}

\frac{d ^{2}}{d x ^{2}} ((y) (x^{2} + y^{2} - 25))

cos (x) (1 + cos (x))

What is expand (6z)/((z-3)(z+1)) ?
The solution to expand (6z)/((z-3)(z+1)) is (6z)/(z^2-2z-3)