What is expand-5r^2sin(θ)(r^2-9) ?

The solution to expand-5r^2sin(θ)(r^2-9) is -5r^4sin(θ)+45r^2sin(θ)

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expand-5r^2sin(θ)(r^2-9)

expand

- 5 r^{2} sin (θ) (r^{2} - 9)

- 5 r^{4} sin (θ) + 45 r^{2} sin (θ)

Solution steps

- 5 r^{2} sin (θ) (r^{2} - 9)

Apply the distributive law:

a (b - c) = ab - a c

- 5 r^{2} sin (θ) (r^{2} - 9) = - 5 r^{2} sin (θ) r^{2} - (- 5 r^{2} sin (θ)) \cdot 9

= - 5 r^{2} sin (θ) r^{2} - (- 5 r^{2} sin (θ)) \cdot 9

Simplify

- 5 r^{2} sin (θ) r^{2} - (- 5 r^{2} sin (θ)) \cdot 9 : - 5 r^{4} sin (θ) + 45 r^{2} sin (θ)

= - 5 r^{4} sin (θ) + 45 r^{2} sin (θ)

\frac{3}{n ( n + 3 )}

(4 a - b) (3 a + 2 b)

\frac{2 x + 1}{x ( x + 1 )}

(x - 1)^{2} + y^{2}

\frac{( ( 2 x ^{(2)} - 4 x + 4 ) )}{( x ^{(2)} )}

What is expand-5r^2sin(θ)(r^2-9) ?
The solution to expand-5r^2sin(θ)(r^2-9) is -5r^4sin(θ)+45r^2sin(θ)