What are the solutions to the equation 4x^2-2x+4=0 ?

The solutions to the equation 4x^2-2x+4=0 are x= 1/4+i(sqrt(15))/4 ,x= 1/4-i(sqrt(15))/4

Find the zeros of 4x^2-2x+4=0

The zeros of 4x^2-2x+4=0 are x= 1/4+i(sqrt(15))/4 ,x= 1/4-i(sqrt(15))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 2 x + 4 = 0

x = \frac{1}{4} + i \frac{15}{4}, x = \frac{1}{4} - i \frac{15}{4}

Solution steps

4 x^{2} - 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

Simplify

(- 2)^{2} - 4 \cdot 4 \cdot 4 : 215 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 15 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 15 i}{2 \cdot 4}, x_{2} = \frac{- ( - 2 ) - 2 15 i}{2 \cdot 4}

x = \frac{- ( - 2 ) + 2 15 i}{2 \cdot 4} : \frac{1}{4} + i \frac{15}{4}

x = \frac{- ( - 2 ) - 2 15 i}{2 \cdot 4} : \frac{1}{4} - i \frac{15}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} + i \frac{15}{4}, x = \frac{1}{4} - i \frac{15}{4}

\frac{4 !}{6 !}

- e^{1 - l o g_{10} (x)} \geq 0

- 6 (- 3 + 6 x) > - 38 - 8 x

- \frac{3}{2} - 1

(- 3 a + 5) (6 a - 1) = 0

What are the solutions to the equation 4x^2-2x+4=0 ?
The solutions to the equation 4x^2-2x+4=0 are x= 1/4+i(sqrt(15))/4 ,x= 1/4-i(sqrt(15))/4
Find the zeros of 4x^2-2x+4=0
The zeros of 4x^2-2x+4=0 are x= 1/4+i(sqrt(15))/4 ,x= 1/4-i(sqrt(15))/4