What is expand (3x-4y+4=0,)(9x-12y-4=0) ?

The solution to expand (3x-4y+4=0,)(9x-12y-4=0) is 27x^2-36xy-12x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (3x-4y+4=0,)(9x-12y-4=0)

expand

(3 x - 4 y + 4 = 0,) (9 x - 12 y - 4 = 0)

27 x^{2} - 36 x y - 12 x = 0

Solution steps

(3 x - 4 y + 4 = 0,) (9 x - 12 y - 4 = 0)

= (3 x - 4 y + 4 \cdot 0 =,) (9 x - 12 y - 4 \cdot 0 =)

Distribute parentheses

3 x \cdot 9 x + 3 x (- 12 y) + 3 x (- 4 = 0) + (- 4 y) \cdot 9 x + (- 4 y) (- 12 y) + (- 4 y) (- 4 = 0) + 4 = 0, 9 x + 4 = 0, (- 12 y) + 4 = 0, (- 4 = 0)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

3 \cdot 9 xx - 3 \cdot 12 x y - 3 \cdot 4 x = 0 - 4 \cdot 9 x y + 4 \cdot 12 yy + 4 \cdot 4 y = 0 + 4 = 0, 9 x - 4 = 0, 12 y - 4 = 0, 4 = 0

Expand

3 \cdot 9 xx - 3 \cdot 12 x y - 3 \cdot 4 x : 27 x^{2} - 36 x y - 12 x

27 x^{2} - 36 x y - 12 x = 0

2 (3 + 5)

4 (\frac{1}{2} x + \frac{3}{2} y)

lo g_{10} (x y z)

(x^{2} + y^{2} + z^{2})^{4}

\frac{1}{x ( x - 3 ) ^{3}}

What is expand (3x-4y+4=0,)(9x-12y-4=0) ?
The solution to expand (3x-4y+4=0,)(9x-12y-4=0) is 27x^2-36xy-12x=0