What is (x+1/2)(x-3/4) ?

The solution to (x+1/2)(x-3/4) is ((2x+1)(4x-3))/8

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simplify (x+1/2)(x-3/4)

simplify

(x + \frac{1}{2}) (x - \frac{3}{4})

\frac{( 2 x + 1 ) ( 4 x - 3 )}{8}

Solution steps

(x + \frac{1}{2}) (x - \frac{3}{4})

Simplify

x + \frac{1}{2} : \frac{2 x + 1}{2}

= \frac{2 x + 1}{2} (x - \frac{3}{4})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 x + 1 ) ( x - \frac{3}{4} )}{2}

Simplify

(2 x + 1) (x - \frac{3}{4}) : \frac{( 2 x + 1 ) ( x \cdot 4 - 3 )}{4}

= \frac{\frac{( 2 x + 1 ) ( x \cdot 4 - 3 )}{4}}{2}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 2 x + 1 ) ( x \cdot 4 - 3 )}{4 \cdot 2}

Multiply the numbers:

4 \cdot 2 = 8

= \frac{( 2 x + 1 ) ( x \cdot 4 - 3 )}{8}

= \frac{( 2 x + 1 ) ( 4 x - 3 )}{8}

\frac{\frac{d}{d x} ( ( x ^{2} - 1 ) ^{2} )}{( 5 x + 8 ) ^{2}}

\frac{x - 2}{( x - 1 ) ^{2}}

(- 1 + i 3)^{5}

(x + y) (x + y^{'} (x))

1 - x^{2} (1 - x^{2})