What is expand 1/8+1/32 (x-1)-21/256 (x-1)^2 ?

The solution to expand 1/8+1/32 (x-1)-21/256 (x-1)^2 is 3/256+(25x)/(128)-(21x^2)/(256)

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expand 1/8+1/32 (x-1)-21/256 (x-1)^2

expand

\frac{1}{8} + \frac{1}{32} (x - 1) - \frac{21}{256} (x - 1)^{2}

\frac{3}{256} + \frac{25 x}{128} - \frac{21 x ^{2}}{256}

Solution steps

\frac{1}{8} + \frac{1}{32} (x - 1) - \frac{21}{256} (x - 1)^{2}

Expand

\frac{1}{32} (x - 1) : \frac{x}{32} - \frac{1}{32}

= \frac{1}{8} + \frac{x}{32} - \frac{1}{32} - \frac{21}{256} (x - 1)^{2}

Expand

- \frac{21}{256} (x - 1)^{2} : - \frac{21 x ^{2}}{256} + \frac{21 x}{128} - \frac{21}{256}

= \frac{1}{8} + \frac{x}{32} - \frac{1}{32} - \frac{21 x ^{2}}{256} + \frac{21 x}{128} - \frac{21}{256}

Join

\frac{1}{8} + \frac{x}{32} - \frac{1}{32} - \frac{21 x ^{2}}{256} + \frac{21 x}{128} - \frac{21}{256} : \frac{3}{256} + \frac{25 x}{128} - \frac{21 x ^{2}}{256}

= \frac{3}{256} + \frac{25 x}{128} - \frac{21 x ^{2}}{256}

\frac{( s ^{2} + 6 )}{( s ( s - 1 ) ( s + 2 ) ( s - 3 ) )}

\frac{4 x ^{2} - 15 x - 1}{( x - 1 ) ( x + 2 ) ( x - 3 )}

π (x + 1)^{2}

\frac{- 3 x ^{2} + 10}{x ^{2} ( x ^{4} - 25 )}

(1 - cos^{2} (x))^{3}

What is expand 1/8+1/32 (x-1)-21/256 (x-1)^2 ?
The solution to expand 1/8+1/32 (x-1)-21/256 (x-1)^2 is 3/256+(25x)/(128)-(21x^2)/(256)