What is expand (2(x+3)(x-2))/((x-4)(x+4)) ?

The solution to expand (2(x+3)(x-2))/((x-4)(x+4)) is (2x^2+2x-12)/(x^2-16)

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expand (2(x+3)(x-2))/((x-4)(x+4))

expand

\frac{2 ( x + 3 ) ( x - 2 )}{( x - 4 ) ( x + 4 )}

\frac{2 x ^{2} + 2 x - 12}{x ^{2} - 16}

Solution steps

\frac{2 ( x + 3 ) ( x - 2 )}{( x - 4 ) ( x + 4 )}

Expand

(x - 4) (x + 4) : x^{2} - 16

= \frac{2 ( x + 3 ) ( x - 2 )}{x ^{2} - 16}

Expand

2 (x + 3) (x - 2) : 2 x^{2} + 2 x - 12

= \frac{2 x ^{2} + 2 x - 12}{x ^{2} - 16}

x (e^{x} - 1)

\frac{1}{( x + 1 ) ( x ^{2} + 1 )}

(1 + e^{2 t})^{3}

\frac{2 ( n + 1 ) ( 2 n + 1 )}{3 n}

\frac{x + 1}{x ^{2} ( x ^{2} + 1 ) ^{2}}

What is expand (2(x+3)(x-2))/((x-4)(x+4)) ?
The solution to expand (2(x+3)(x-2))/((x-4)(x+4)) is (2x^2+2x-12)/(x^2-16)