What is expand ((n+1)(2n+1))/(6n^2) ?

The solution to expand ((n+1)(2n+1))/(6n^2) is 1/3+1/(2n)+1/(6n^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((n+1)(2n+1))/(6n^2)

expand

\frac{( n + 1 ) ( 2 n + 1 )}{6 n ^{2}}

\frac{1}{3} + \frac{1}{2 n} + \frac{1}{6 n ^{2}}

Solution steps

\frac{( n + 1 ) ( 2 n + 1 )}{6 n ^{2}}

Expand

(n + 1) (2 n + 1) : 2 n^{2} + 3 n + 1

= \frac{2 n ^{2} + 3 n + 1}{6 n ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 n ^{2} + 3 n + 1}{6 n ^{2}} = \frac{2 n ^{2}}{6 n ^{2}} + \frac{3 n}{6 n ^{2}} + \frac{1}{6 n ^{2}}

= \frac{2 n ^{2}}{6 n ^{2}} + \frac{3 n}{6 n ^{2}} + \frac{1}{6 n ^{2}}

Cancel

\frac{2 n ^{2}}{6 n ^{2}} : \frac{1}{3}

= \frac{1}{3} + \frac{3 n}{6 n ^{2}} + \frac{1}{6 n ^{2}}

Cancel

\frac{3 n}{6 n ^{2}} : \frac{1}{2 n}

= \frac{1}{3} + \frac{1}{2 n} + \frac{1}{6 n ^{2}}

\frac{3 ( x + 2 )}{2 x}

(1 + i)^{4}

t (e^{t} + e^{4 t})^{2}

\frac{1}{( s - 1 ) ^{2} ( s ^{2} - 2 s + 1 )}

What is expand ((n+1)(2n+1))/(6n^2) ?
The solution to expand ((n+1)(2n+1))/(6n^2) is 1/3+1/(2n)+1/(6n^2)