What is expand (8y+6)/((4y-9)(y+2)) ?

The solution to expand (8y+6)/((4y-9)(y+2)) is (8y+6)/(4y^2-y-18)

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expand (8y+6)/((4y-9)(y+2))

expand

\frac{8 y + 6}{( 4 y - 9 ) ( y + 2 )}

\frac{8 y + 6}{4 y ^{2} - y - 18}

Solution steps

\frac{8 y + 6}{( 4 y - 9 ) ( y + 2 )}

Expand

(4 y - 9) (y + 2) : 4 y^{2} - y - 18

= \frac{8 y + 6}{4 y ^{2} - y - 18}

sin (x) cos (x) (- csc (x) + sec (x))

\frac{1}{4} (e^{2 x} \cdot 2 x - e^{2 x})

(- 3 + 4 i)^{4}

(x^{3} - x + 30)^{5}

What is expand (8y+6)/((4y-9)(y+2)) ?
The solution to expand (8y+6)/((4y-9)(y+2)) is (8y+6)/(4y^2-y-18)