What is expand 3((x^2-5)-(3x^2+4)=x+1) ?

The solution to expand 3((x^2-5)-(3x^2+4)=x+1) is -6x^2-27=x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 3((x^2-5)-(3x^2+4)=x+1)

expand

3 ((x^{2} - 5) - (3 x^{2} + 4) = x + 1)

- 6 x^{2} - 27 = x + 3

Solution steps

3 ((x^{2} - 5) - (3 x^{2} + 4) = x + 1)

= 3 ((x^{2} - 5) - = x (3 x^{2} + 4) + 1)

Distribute parentheses

= 3 (x^{2} - 5) + 3 (- (3 x^{2} + 4) = x) + 3 \cdot 1

Apply minus-plus rules

+ (- a) = - a

3 (x^{2} - 5) - 3 (3 x^{2} + 4) = x + 3 \cdot 1

Simplify

3 (x^{2} - 5) - 3 (3 x^{2} + 4) = x + 3 \cdot 1 : - 6 x^{2} - 27 = x + 3

- 6 x^{2} - 27 = x + 3

(cos (x) + 3 sin (x))^{2}

(sin (2 x))^{2}

\frac{x ^{3}}{( x - 2 ) ( x + 1 )}

(tan (x) - sin (x))^{2} + (1 - cos (x))^{2}

sin (0)

What is expand 3((x^2-5)-(3x^2+4)=x+1) ?
The solution to expand 3((x^2-5)-(3x^2+4)=x+1) is -6x^2-27=x+3