What is expand (x-1)/(2(x-4)^2) ?

The solution to expand (x-1)/(2(x-4)^2) is (x-1)/(2x^2-16x+32)

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expand (x-1)/(2(x-4)^2)

expand

\frac{x - 1}{2 ( x - 4 ) ^{2}}

\frac{x - 1}{2 x ^{2} - 16 x + 32}

Solution steps

\frac{x - 1}{2 ( x - 4 ) ^{2}}

(x - 4)^{2} = x^{2} - 8 x + 16

= \frac{x - 1}{2 ( x ^{2} - 8 x + 16 )}

Expand

2 (x^{2} - 8 x + 16) : 2 x^{2} - 16 x + 32

= \frac{x - 1}{2 x ^{2} - 16 x + 32}

3 (x - 4 = 13)

\frac{x - 2}{x ( x ^{2} - 4 x + 5 ) ^{2}}

(t cos (t) + sin (t))^{2}

(3 x - 2 + 4) (3 x - 2 - 4)

\frac{4 x - 8}{( x - 4 ) ( x + 1 )}

What is expand (x-1)/(2(x-4)^2) ?
The solution to expand (x-1)/(2(x-4)^2) is (x-1)/(2x^2-16x+32)