What is expand (4x-8)/((x-4)(x+1)) ?

The solution to expand (4x-8)/((x-4)(x+1)) is (4x-8)/(x^2-3x-4)

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expand (4x-8)/((x-4)(x+1))

expand

\frac{4 x - 8}{( x - 4 ) ( x + 1 )}

\frac{4 x - 8}{x ^{2} - 3 x - 4}

Solution steps

\frac{4 x - 8}{( x - 4 ) ( x + 1 )}

Expand

(x - 4) (x + 1) : x^{2} - 3 x - 4

= \frac{4 x - 8}{x ^{2} - 3 x - 4}

\frac{x ^{2} - 6 x + 8}{( 2 x - 3 ) ^{2}}

\frac{2 ( x + h ) - 1 - 2 x - 1}{h}

\frac{d}{d y} ((x) (x^{2} + y^{2}))

(1 + 2 e^{x})^{3}

(5 + 3 x 2) (3 x + 2)

What is expand (4x-8)/((x-4)(x+1)) ?
The solution to expand (4x-8)/((x-4)(x+1)) is (4x-8)/(x^2-3x-4)