What are the solutions to the equation 3x^2+24x+9=0 ?

The solutions to the equation 3x^2+24x+9=0 are x=-4+sqrt(13),x=-4-sqrt(13)

Find the zeros of 3x^2+24x+9=0

The zeros of 3x^2+24x+9=0 are x=-4+sqrt(13),x=-4-sqrt(13)

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3 x^{2} + 24 x + 9 = 0

x = - 4 + 13, x = - 4 - 13

Decimal Notation

x = - 0.39444 \dots, x = - 7.60555 \dots

Solution steps

3 x^{2} + 24 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 \cdot 9 = 613

x_{1, 2} = \frac{- 24 \pm 6 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 24 + 6 13}{2 \cdot 3}, x_{2} = \frac{- 24 - 6 13}{2 \cdot 3}

x = \frac{- 24 + 6 13}{2 \cdot 3} : - 4 + 13

x = \frac{- 24 - 6 13}{2 \cdot 3} : - 4 - 13

The solutions to the quadratic equation are:

x = - 4 + 13, x = - 4 - 13

10 x^{2} - 105 x + 135

2000 (x - 0.03) = 6000

w^{2} - 36

x^{\frac{1}{3}} \cdot x

\frac{x - 3}{x + 4} > 3

What are the solutions to the equation 3x^2+24x+9=0 ?
The solutions to the equation 3x^2+24x+9=0 are x=-4+sqrt(13),x=-4-sqrt(13)
Find the zeros of 3x^2+24x+9=0
The zeros of 3x^2+24x+9=0 are x=-4+sqrt(13),x=-4-sqrt(13)