What is expand ((n+1)(x+2))/(3n) ?

The solution to expand ((n+1)(x+2))/(3n) is x/3+2/3+x/(3n)+2/(3n)

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expand ((n+1)(x+2))/(3n)

expand

\frac{( n + 1 ) ( x + 2 )}{3 n}

\frac{x}{3} + \frac{2}{3} + \frac{x}{3 n} + \frac{2}{3 n}

Solution steps

\frac{( n + 1 ) ( x + 2 )}{3 n}

Expand

(n + 1) (x + 2) : n x + 2 n + x + 2

= \frac{n x + 2 n + x + 2}{3 n}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n x + 2 n + x + 2}{3 n} = \frac{n x}{3 n} + \frac{2 n}{3 n} + \frac{x}{3 n} + \frac{2}{3 n}

= \frac{n x}{3 n} + \frac{2 n}{3 n} + \frac{x}{3 n} + \frac{2}{3 n}

Cancel

\frac{n x}{3 n} : \frac{x}{3}

= \frac{x}{3} + \frac{2 n}{3 n} + \frac{x}{3 n} + \frac{2}{3 n}

Cancel

\frac{2 n}{3 n} : \frac{2}{3}

= \frac{x}{3} + \frac{2}{3} + \frac{x}{3 n} + \frac{2}{3 n}

2 e^{35} \cdot \frac{d}{d s} (\frac{1}{e ^{35} ( s + 5 )})

e^{t} (- t e^{- t} - e^{- t} + 1)

x^{\frac{1 - 2 x}{x}} (- ln (x) + 1)

(1, \frac{13}{2}) y (6, - 4)

(2 x + 1) (2 x - 1)

What is expand ((n+1)(x+2))/(3n) ?
The solution to expand ((n+1)(x+2))/(3n) is x/3+2/3+x/(3n)+2/(3n)