What is expand (6/7-x)^4 ?

The solution to expand (6/7-x)^4 is 1296/2401-(864x}{343}+(216x^2)/(49)-\frac{24x^3)/7+x^4

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expand (6/7-x)^4

expand

(\frac{6}{7} - x)^{4}

\frac{1296}{2401} - \frac{864 x}{343} + \frac{216 x ^{2}}{49} - \frac{24 x ^{3}}{7} + x^{4}

Solution steps

(\frac{6}{7} - x)^{4}

Apply binomial theorem:

(a + b)^{n} = i = 0 \sum n (i n) a^{(n - i)} b^{i}

a = \frac{6}{7}, b = - x

= i = 0 \sum 4 (i 4) (\frac{6}{7})^{(4 - i)} (- x)^{i}

Expand summation

= \frac{4 !}{0 ! ( 4 - 0 ) !} (\frac{6}{7})^{4} (- x)^{0} + \frac{4 !}{1 ! ( 4 - 1 ) !} (\frac{6}{7})^{3} (- x)^{1} + \frac{4 !}{2 ! ( 4 - 2 ) !} (\frac{6}{7})^{2} (- x)^{2} + \frac{4 !}{3 ! ( 4 - 3 ) !} (\frac{6}{7})^{1} (- x)^{3} + \frac{4 !}{4 ! ( 4 - 4 ) !} (\frac{6}{7})^{0} (- x)^{4}

Simplify

\frac{4 !}{0 ! ( 4 - 0 ) !} (\frac{6}{7})^{4} (- x)^{0} : \frac{1296}{2401}

Simplify

\frac{4 !}{1 ! ( 4 - 1 ) !} (\frac{6}{7})^{3} (- x)^{1} : - \frac{864 x}{343}

Simplify

\frac{4 !}{2 ! ( 4 - 2 ) !} (\frac{6}{7})^{2} (- x)^{2} : \frac{216 x ^{2}}{49}

Simplify

\frac{4 !}{3 ! ( 4 - 3 ) !} (\frac{6}{7})^{1} (- x)^{3} : - \frac{24 x ^{3}}{7}

Simplify

\frac{4 !}{4 ! ( 4 - 4 ) !} (\frac{6}{7})^{0} (- x)^{4} : x^{4}

= \frac{1296}{2401} - \frac{864 x}{343} + \frac{216 x ^{2}}{49} - \frac{24 x ^{3}}{7} + x^{4}

(y^{2} - 2 x y + 6 x) d x + (x^{2} - 2 x y + 2) d y

(a + 2 + \frac{7}{a - 5}) (a - 2 - \frac{5}{a + 2})

(a + b)^{3}

\frac{x ^{2} + 2 x - 1}{( x + 1 ) ^{2}}

\frac{2}{( n + 1 ) ( n + 3 )}

What is expand (6/7-x)^4 ?
The solution to expand (6/7-x)^4 is 1296/2401-(864x}{343}+(216x^2)/(49)-\frac{24x^3)/7+x^4