What is expand (2s+1)/((s^2+1)(s-1)(s-3)) ?

The solution to expand (2s+1)/((s^2+1)(s-1)(s-3)) is (2s+1)/(s^4-4s^3+4s^2-4s+3)

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expand (2s+1)/((s^2+1)(s-1)(s-3))

expand

\frac{2 s + 1}{( s ^{2} + 1 ) ( s - 1 ) ( s - 3 )}

\frac{2 s + 1}{s ^{4} - 4 s ^{3} + 4 s ^{2} - 4 s + 3}

Solution steps

\frac{2 s + 1}{( s ^{2} + 1 ) ( s - 1 ) ( s - 3 )}

Expand

(s^{2} + 1) (s - 1) (s - 3) : s^{4} - 4 s^{3} + 4 s^{2} - 4 s + 3

= \frac{2 s + 1}{s ^{4} - 4 s ^{3} + 4 s ^{2} - 4 s + 3}

ln (\frac{y}{1 - y})

(e^{x} + 3)^{2}

\frac{( 1 - e ^{(- 2 \cdot s)} )}{( s \cdot ( s ^{2} + 2 \cdot s + 26 ) )}

(1 - 2 i)^{6}

What is expand (2s+1)/((s^2+1)(s-1)(s-3)) ?
The solution to expand (2s+1)/((s^2+1)(s-1)(s-3)) is (2s+1)/(s^4-4s^3+4s^2-4s+3)