What is (x+2/5)(x-1/5) ?

The solution to (x+2/5)(x-1/5) is ((5x+2)(5x-1))/(25)

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simplify (x+2/5)(x-1/5)

simplify

(x + \frac{2}{5}) (x - \frac{1}{5})

\frac{( 5 x + 2 ) ( 5 x - 1 )}{25}

Solution steps

(x + \frac{2}{5}) (x - \frac{1}{5})

Simplify

x + \frac{2}{5} : \frac{5 x + 2}{5}

= \frac{5 x + 2}{5} (x - \frac{1}{5})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 5 x + 2 ) ( x - \frac{1}{5} )}{5}

Simplify

(5 x + 2) (x - \frac{1}{5}) : \frac{( 5 x + 2 ) ( x \cdot 5 - 1 )}{5}

= \frac{\frac{( 5 x + 2 ) ( x \cdot 5 - 1 )}{5}}{5}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 5 x + 2 ) ( x \cdot 5 - 1 )}{5 \cdot 5}

Multiply the numbers:

5 \cdot 5 = 25

= \frac{( 5 x + 2 ) ( x \cdot 5 - 1 )}{25}

= \frac{( 5 x + 2 ) ( 5 x - 1 )}{25}

t (x) x^{^{''}} + (4 t (x) - 6) x^{^{'}} + 4 x

(x - 3) (x - \frac{1}{2})

5 \cdot (x + 4 y = 14)

y^{''} (x) (3 + \frac{1}{x})^{3}

(e^{i wt} - e^{- i wt}) e^{- in wt}