What is expand log_{4}(2)x^2(x+1) ?

The solution to expand log_{4}(2)x^2(x+1) is 1/2 x^3+1/2 x^2

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expand log_{4}(2)x^2(x+1)

expand

lo g_{4} (2) x^{2} (x + 1)

\frac{1}{2} x^{3} + \frac{1}{2} x^{2}

Solution steps

lo g_{4} (2) x^{2} (x + 1)

Apply the distributive law:

a (b + c) = ab + a c

lo g_{4} (2) x^{2} (x + 1) = lo g_{4} (2) x^{2} x + lo g_{4} (2) x^{2} \cdot 1

= lo g_{4} (2) x^{2} x + lo g_{4} (2) x^{2} \cdot 1

Simplify

lo g_{4} (2) x^{2} x + lo g_{4} (2) x^{2} \cdot 1 : \frac{1}{2} x^{3} + \frac{1}{2} x^{2}

= \frac{1}{2} x^{3} + \frac{1}{2} x^{2}

- \frac{4}{s ( s ^{2} - 2 s )}

\frac{d ^{2}}{d x ^{2}} ((f (x)) (4 x^{3} - 6 x^{2} + 3))

(1 + i 3)^{10}

(1 + 4 x)^{2}

(3 x^{2} - \frac{1}{10}) (3 x^{2} + \frac{1}{10})

What is expand log_{4}(2)x^2(x+1) ?
The solution to expand log_{4}(2)x^2(x+1) is 1/2 x^3+1/2 x^2