What is expand sin(t)U(t-pi/2) ?

The solution to expand sin(t)U(t-pi/2) is tUsin(t)-(piUsin(t))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand sin(t)U(t-pi/2)

expand

sin (t) U (t - \frac{π}{2})

t U sin (t) - \frac{π U sin ( t )}{2}

Solution steps

sin (t) U (t - \frac{π}{2})

= U sin (t) (t - \frac{π}{2})

Apply the distributive law:

a (b - c) = ab - a c

a = sin (t) U, b = t, c = \frac{π}{2}

= sin (t) U t - sin (t) U \frac{π}{2}

= t U sin (t) - \frac{π}{2} U sin (t)

Simplify

t U sin (t) - \frac{π}{2} U sin (t) : t U sin (t) - \frac{π U sin ( t )}{2}

= t U sin (t) - \frac{π U sin ( t )}{2}

(sin (9 x) + sin (x)) csc (5 x)

l im θ \Rightarrow π^{2} (tan (θ) - sec (θ))

(1 - cos (t))^{2} + sin^{2} (t)

(t cos (2 t) + sin (t))^{2}

\frac{d}{d t} ((x) 200 (30 - t^{2}))

What is expand sin(t)U(t-pi/2) ?
The solution to expand sin(t)U(t-pi/2) is tUsin(t)-(piUsin(t))/2