What is expand (x(x-1)(x-2)(x-3))/(24) ?

The solution to expand (x(x-1)(x-2)(x-3))/(24) is (x^4}{24}-(x^3)/4+\frac{11x^2)/(24)-x/4

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expand (x(x-1)(x-2)(x-3))/(24)

expand

\frac{x ( x - 1 ) ( x - 2 ) ( x - 3 )}{24}

\frac{x ^{4}}{24} - \frac{x ^{3}}{4} + \frac{11 x ^{2}}{24} - \frac{x}{4}

Solution steps

\frac{x ( x - 1 ) ( x - 2 ) ( x - 3 )}{24}

Expand

x (x - 1) (x - 2) (x - 3) : x^{4} - 6 x^{3} + 11 x^{2} - 6 x

= \frac{x ^{4} - 6 x ^{3} + 11 x ^{2} - 6 x}{24}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{4} - 6 x ^{3} + 11 x ^{2} - 6 x}{24} = \frac{x ^{4}}{24} - \frac{6 x ^{3}}{24} + \frac{11 x ^{2}}{24} - \frac{6 x}{24}

= \frac{x ^{4}}{24} - \frac{6 x ^{3}}{24} + \frac{11 x ^{2}}{24} - \frac{6 x}{24}

Cancel

\frac{6 x ^{3}}{24} : \frac{x ^{3}}{4}

= \frac{x ^{4}}{24} - \frac{x ^{3}}{4} + \frac{11 x ^{2}}{24} - \frac{6 x}{24}

Cancel

\frac{6 x}{24} : \frac{x}{4}

= \frac{x ^{4}}{24} - \frac{x ^{3}}{4} + \frac{11 x ^{2}}{24} - \frac{x}{4}

lo g_{10} (2) (x + 2)

\frac{4 + 3 y ^{2}}{y ( y + 2 )}

\frac{e ^{z}}{( ( z - 1 ) ^{3} ( z - 3 ) )}

\frac{9 ( n + 1 ) ( 2 n + 1 )}{2 n ^{2}}

(2 x - 3)^{2}

What is expand (x(x-1)(x-2)(x-3))/(24) ?
The solution to expand (x(x-1)(x-2)(x-3))/(24) is (x^4}{24}-(x^3)/4+\frac{11x^2)/(24)-x/4