What is expand (sin(z))/((z-1)(z+1)^2) ?

The solution to expand (sin(z))/((z-1)(z+1)^2) is (sin(z))/(z^3+z^2-z-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (sin(z))/((z-1)(z+1)^2)

expand

\frac{sin ( z )}{( z - 1 ) ( z + 1 ) ^{2}}

\frac{sin ( z )}{z ^{3} + z ^{2} - z - 1}

Solution steps

\frac{sin ( z )}{( z - 1 ) ( z + 1 ) ^{2}}

(z + 1)^{2} = z^{2} + 2 z + 1

= \frac{sin ( z )}{( z - 1 ) ( z ^{2} + 2 z + 1 )}

Expand

(z - 1) (z^{2} + 2 z + 1) : z^{3} + z^{2} - z - 1

= \frac{sin ( z )}{z ^{3} + z ^{2} - z - 1}

x (x + 2)^{2}

(3 x^{4} - y) d x + (x - 4 x^{2} y^{3}) d y

(x - \frac{1}{2}) (x + 1)

(2 + 5) (5 - 7)

\frac{1 - e ^{- s}}{s ^{2} ( 2 s + 1 )}

What is expand (sin(z))/((z-1)(z+1)^2) ?
The solution to expand (sin(z))/((z-1)(z+1)^2) is (sin(z))/(z^3+z^2-z-1)