What is expand-2(x+Δx)^2 ?

The solution to expand-2(x+Δx)^2 is -2x^2-4Δx^2-2Δ^2x^2

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expand-2(x+Δx)^2

expand

- 2 (x + Δ x)^{2}

- 2 x^{2} - 4Δ x^{2} - 2 Δ^{2} x^{2}

Solution steps

- 2 (x + Δ x)^{2}

(x + Δ x)^{2} = x^{2} + 2Δ x^{2} + Δ^{2} x^{2}

= - 2 (x^{2} + 2Δ x^{2} + Δ^{2} x^{2})

Distribute parentheses

= (- 2) x^{2} + (- 2) \cdot 2Δ x^{2} + (- 2) Δ^{2} x^{2}

Apply minus-plus rules

+ (- a) = - a

= - 2 x^{2} - 2 \cdot 2Δ x^{2} - 2 Δ^{2} x^{2}

Multiply the numbers:

2 \cdot 2 = 4

= - 2 x^{2} - 4Δ x^{2} - 2 Δ^{2} x^{2}

δ (x - 2 π)

x (x^{3} e^{7 x} + 4)

(x + y) sin (\frac{π}{x + y})

(5 x^{4} - 6 x^{3} + x)^{5}

\frac{1}{s ^{2}} - \frac{e ^{- s}}{s ( 1 - e ^{- s} )}

What is expand-2(x+Δx)^2 ?
The solution to expand-2(x+Δx)^2 is -2x^2-4Δx^2-2Δ^2x^2