What is expand ((x-2)(x-4))/8 ?

The solution to expand ((x-2)(x-4))/8 is (x^2)/8-(3x)/4+1

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expand ((x-2)(x-4))/8

expand

\frac{( x - 2 ) ( x - 4 )}{8}

\frac{x ^{2}}{8} - \frac{3 x}{4} + 1

Solution steps

\frac{( x - 2 ) ( x - 4 )}{8}

Expand

(x - 2) (x - 4) : x^{2} - 6 x + 8

= \frac{x ^{2} - 6 x + 8}{8}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 6 x + 8}{8} = \frac{x ^{2}}{8} - \frac{6 x}{8} + \frac{8}{8}

= \frac{x ^{2}}{8} - \frac{6 x}{8} + \frac{8}{8}

Apply rule

\frac{a}{a} = 1

\frac{8}{8} = 1

= \frac{x ^{2}}{8} - \frac{6 x}{8} + 1

Cancel

\frac{6 x}{8} : \frac{3 x}{4}

= \frac{x ^{2}}{8} - \frac{3 x}{4} + 1

\frac{1}{( 1 - x ) ( a - 2 x )}

lo g_{10} (\frac{9 x - 6}{x + 6})

3 (2 - 1)

\frac{3}{s ^{2} ( s ^{2} - 9 )}

(x - 1) (x - \frac{1}{2})

What is expand ((x-2)(x-4))/8 ?
The solution to expand ((x-2)(x-4))/8 is (x^2)/8-(3x)/4+1