What is (x^2+1)(x+5+1/x) ?

The solution to (x^2+1)(x+5+1/x) is ((x^2+1)(x^2+5x+1))/x

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simplify (x^2+1)(x+5+1/x)

simplify

(x^{2} + 1) (x + 5 + \frac{1}{x})

\frac{( x ^{2} + 1 ) ( x ^{2} + 5 x + 1 )}{x}

Solution steps

(x^{2} + 1) (x + 5 + \frac{1}{x})

Join

x + 5 + \frac{1}{x} : \frac{x ^{2} + 5 x + 1}{x}

= (x^{2} + 1) \frac{x ^{2} + 5 x + 1}{x}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x ^{2} + 1 ) ( x ^{2} + 5 x + 1 )}{x}

A (3, - 1) B (- 2, - 4)

(4 x^{3} - 4 x^{4} - 3) d x

\frac{( 2 s + 1 ) ( s + 2 )}{6 s ^{4} + 35 s ^{3} + 14 s ^{2} + 20 s + 6}

\frac{( x - 4 ) ( x + 8 )}{( x - 6 ) ^{2}}

\frac{x ( x - 1 )}{x - 2}

What is (x^2+1)(x+5+1/x) ?
The solution to (x^2+1)(x+5+1/x) is ((x^2+1)(x^2+5x+1))/x