What is expand 9/((1-x)(1+2x)^2) ?

The solution to expand 9/((1-x)(1+2x)^2) is 9/(-4x^3+3x+1)

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expand 9/((1-x)(1+2x)^2)

expand

\frac{9}{( 1 - x ) ( 1 + 2 x ) ^{2}}

\frac{9}{- 4 x ^{3} + 3 x + 1}

Solution steps

\frac{9}{( 1 - x ) ( 1 + 2 x ) ^{2}}

(1 + 2 x)^{2} = 1 + 4 x + 4 x^{2}

= \frac{9}{( - x + 1 ) ( 4 x ^{2} + 4 x + 1 )}

Expand

(1 - x) (1 + 4 x + 4 x^{2}) : - 4 x^{3} + 3 x + 1

= \frac{9}{- 4 x ^{3} + 3 x + 1}

\frac{1}{2 ( n ^{2} - n )}

cos (x) d y - (2 y sin (x) - 3) d x

\frac{3 s + 5}{( s + 1 ) ( s ^{2} + 3 s + 2 )}

(7 - 5 i)^{7}

\frac{x ^{4} - 3 x ^{2}}{( x ^{2} - 1 ) ^{2}}

What is expand 9/((1-x)(1+2x)^2) ?
The solution to expand 9/((1-x)(1+2x)^2) is 9/(-4x^3+3x+1)