What is expand cos^2(x)(1+tan^2(x)=1) ?

The solution to expand cos^2(x)(1+tan^2(x)=1) is cos^2(x)+cos^2(x)tan^2(x)=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand cos^2(x)(1+tan^2(x)=1)

expand

cos^{2} (x) (1 + tan^{2} (x) = 1)

cos^{2} (x) + cos^{2} (x) tan^{2} (x) = 1

Solution steps

cos^{2} (x) (1 + tan^{2} (x) = 1)

= cos^{2} (x) (1 + 1 = tan^{2} (x))

Apply the distributive law:

a (b + c) = ab + a c

a = cos^{2} (x), b = 1, c = tan^{2} (x) = 1

cos^{2} (x) \cdot 1 + cos^{2} (x) tan^{2} (x) = 1

1 \cdot cos^{2} (x) + cos^{2} (x) tan^{2} (x) = 1

Expand

1 \cdot cos^{2} (x) + cos^{2} (x) tan^{2} (x) : cos^{2} (x) + cos^{2} (x) tan^{2} (x)

cos^{2} (x) + cos^{2} (x) tan^{2} (x) = 1

(cos (x) - sin (x)) (sec (x) + csc (x))

(2 + t) 9 - t^{2}

\frac{e ^{t} ( cos ( t ) - 1 )}{t}

(x - 2)^{2} + y^{2}

(x + \frac{1}{4}) (x - \frac{1}{4})

What is expand cos^2(x)(1+tan^2(x)=1) ?
The solution to expand cos^2(x)(1+tan^2(x)=1) is cos^2(x)+cos^2(x)tan^2(x)=1