What is expand (s-1)/(s(s^3+3s^2-s+6)) ?

The solution to expand (s-1)/(s(s^3+3s^2-s+6)) is (s-1)/(s^4+3s^3-s^2+6s)

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expand (s-1)/(s(s^3+3s^2-s+6))

expand

\frac{s - 1}{s ( s ^{3} + 3 s ^{2} - s + 6 )}

\frac{s - 1}{s ^{4} + 3 s ^{3} - s ^{2} + 6 s}

Solution steps

\frac{s - 1}{s ( s ^{3} + 3 s ^{2} - s + 6 )}

Expand

s (s^{3} + 3 s^{2} - s + 6) : s^{4} + 3 s^{3} - s^{2} + 6 s

= \frac{s - 1}{s ^{4} + 3 s ^{3} - s ^{2} + 6 s}

(6 x y - 2 y^{2} + 1) d x + (3 x^{2} - 4 x y) d y

x (3 x - 2) d x

(4 - 7 i)^{4}

\frac{k ( k + 1 ) ( 2 k + 1 )}{6} + (k + 1)

(e^{- x} - x e^{- x})^{2}

What is expand (s-1)/(s(s^3+3s^2-s+6)) ?
The solution to expand (s-1)/(s(s^3+3s^2-s+6)) is (s-1)/(s^4+3s^3-s^2+6s)