What is 3(((-1)^{k-1}+1)/2+3^{k-1}) ?

The solution to 3(((-1)^{k-1}+1)/2+3^{k-1}) is (3(2*3^{k-1}+(-1)^{k-1}+1))/2

Popular >

simplify 3(((-1)^{k-1}+1)/2+3^{k-1})

simplify

3 (\frac{( - 1 ) ^{k - 1} + 1}{2} + 3^{k - 1})

\frac{3 ( 2 \cdot 3 ^{k - 1} + ( - 1 ) ^{k - 1} + 1 )}{2}

Solution steps

3 (\frac{( - 1 ) ^{k - 1} + 1}{2} + 3^{k - 1})

Join

\frac{( - 1 ) ^{k - 1} + 1}{2} + 3^{k - 1} : \frac{3 ^{k - 1} \cdot 2 + ( - 1 ) ^{k - 1} + 1}{2}

= 3 \cdot \frac{3 ^{k - 1} \cdot 2 + ( - 1 ) ^{k - 1} + 1}{2}

= 3 \cdot \frac{2 \cdot 3 ^{k - 1} + ( - 1 ) ^{k - 1} + 1}{2}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 ( 2 \cdot 3 ^{k - 1} + ( - 1 ) ^{k - 1} + 1 )}{2}

\frac{a + b}{( ( d + e ) \cdot ( a - c ) )}

(x^{2} - 2 y) d x + (2 x y - 3 x^{2}) d y

2 cos (t) (3 - 7 tan (t))

\frac{20}{( x - 1 ) ( x + 1 )}

- 6 \cdot (x + y + z)^{2}

What is 3(((-1)^{k-1}+1)/2+3^{k-1}) ?
The solution to 3(((-1)^{k-1}+1)/2+3^{k-1}) is (3(2*3^{k-1}+(-1)^{k-1}+1))/2