What is expand f(x,y)3y((x^3)/2-1) ?

The solution to expand f(x,y)3y((x^3)/2-1) is 3f(x^3)/2 y(,xy)-3*1*fy(,xy)

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expand f(x,y)3y((x^3)/2-1)

expand

f (x, y) 3 y (\frac{x ^{3}}{2} - 1)

3 f \frac{x ^{3}}{2} y (, x y) - 3 \cdot 1 \cdot f y (, x y)

Solution steps

f (x, y) \cdot 3 y (\frac{x ^{3}}{2} - 1)

= 3 f y (, x y) (\frac{x ^{3}}{2} - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = f (x, y) \cdot 3 y, b = \frac{x ^{3}}{2}, c = 1

= f (x, y) \cdot 3 y \frac{x ^{3}}{2} - f (x, y) \cdot 3 y \cdot 1

= 3 f \frac{x ^{3}}{2} y (, x y) - 3 \cdot 1 \cdot f y (, x y)

\frac{- 4 x + 57}{3 ( 19 - x ) ^{\frac{2}{3}}}

(1 + 2 cos (x))^{2}

\frac{( x + h ) ^{2} - 1 - x ^{2} - 1}{h}

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(2 x - 3 y^{2}) d x

What is expand f(x,y)3y((x^3)/2-1) ?
The solution to expand f(x,y)3y((x^3)/2-1) is 3f(x^3)/2 y(,xy)-3*1*fy(,xy)