What are the solutions to the equation (x-3)(x+2)=0 ?

The solutions to the equation (x-3)(x+2)=0 are x=3,x=-2

Find the zeros of (x-3)(x+2)=0

The zeros of (x-3)(x+2)=0 are x=3,x=-2

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(x - 3) (x + 2) = 0

x = 3, x = - 2

Solution steps

(x - 3) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 2 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 2 = 0 : x = - 2

The solutions to the quadratic equation are:

x = 3, x = - 2

\frac{x}{x + 1} \geq \frac{2}{x}

4 y^{2} + 25 y + 6

- \frac{7}{2} + 7

20 x^{2} - 39 x + 80 = 0

\frac{1}{2} (x - 3) - \frac{3}{5} (2 x - 5) = 3 - \frac{3}{4} (2 x - 6)

What are the solutions to the equation (x-3)(x+2)=0 ?
The solutions to the equation (x-3)(x+2)=0 are x=3,x=-2
Find the zeros of (x-3)(x+2)=0
The zeros of (x-3)(x+2)=0 are x=3,x=-2