What is expand (t-4)sin(2(t-4)\H(t-4)) ?

The solution to expand (t-4)sin(2(t-4)\H(t-4)) is tsin(2t\H(t-4)-8\H(t-4))-4sin(2t\H(t-4)-8\H(t-4))

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expand (t-4)sin(2(t-4)\H(t-4))

expand

(t - 4) sin (2 (t - 4) H (t - 4))

t sin (2 t H (t - 4) - 8 H (t - 4)) - 4 sin (2 t H (t - 4) - 8 H (t - 4))

Solution steps

(t - 4) sin (2 (t - 4) H (t - 4))

= sin (2 H (t - 4) (t - 4)) (t - 4)

Apply the distributive law:

a (b - c) = ab - a c

a = sin (2 (t - 4) H (t - 4)), b = t, c = 4

= sin (2 (t - 4) H (t - 4)) t - sin (2 (t - 4) H (t - 4)) \cdot 4

= t sin (2 H (t - 4) (t - 4)) - 4 sin (2 H (t - 4) (t - 4))

Simplify

t sin (2 H (t - 4) (t - 4)) - 4 sin (2 H (t - 4) (t - 4)) : t sin (2 t H (t - 4) - 8 H (t - 4)) - 4 sin (2 t H (t - 4) - 8 H (t - 4))

= t sin (2 t H (t - 4) - 8 H (t - 4)) - 4 sin (2 t H (t - 4) - 8 H (t - 4))

(3 - 3 i)^{4}

\frac{( x - 2 ) ^{2}}{25}

\frac{1}{( 1 - 2 x ) ^{3}}

\frac{20 e ^{- 4 s}}{s ( s ^{2} + 4 s + 20 )}

x (6 + 5 x)

What is expand (t-4)sin(2(t-4)\H(t-4)) ?
The solution to expand (t-4)sin(2(t-4)\H(t-4)) is tsin(2t\H(t-4)-8\H(t-4))-4sin(2t\H(t-4)-8\H(t-4))