What is expand (1+6sin(θ))^2 ?

The solution to expand (1+6sin(θ))^2 is 1+12sin(θ)+36sin^2(θ)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (1+6sin(θ))^2

expand

(1 + 6 sin (θ))^{2}

1 + 12 sin (θ) + 36 sin^{2} (θ)

Solution steps

(1 + 6 sin (θ))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(1 + 6 sin (θ))^{2} = 1^{2} + 2 \cdot 1 \cdot 6 sin (θ) + (6 sin (θ))^{2}

= 1^{2} + 2 \cdot 1 \cdot 6 sin (θ) + (6 sin (θ))^{2}

Simplify

1^{2} + 2 \cdot 1 \cdot 6 sin (θ) + (6 sin (θ))^{2} : 1 + 12 sin (θ) + 36 sin^{2} (θ)

= 1 + 12 sin (θ) + 36 sin^{2} (θ)

(2 n + 3)!

22 (- 4 - 13)

P (- 3, - 5) y Q (- 8, - 3)

(1 + \frac{2 x}{n})^{3}

\frac{s}{( s ^{2} + 1 ) ( s ^{2} - 2 s + 2 )}

What is expand (1+6sin(θ))^2 ?
The solution to expand (1+6sin(θ))^2 is 1+12sin(θ)+36sin^2(θ)