What is expand sin(t)u(t-2pi) ?

The solution to expand sin(t)u(t-2pi) is tusin(t)-2piusin(t)

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expand sin(t)u(t-2pi)

expand

sin (t) u (t - 2 π)

t u sin (t) - 2 π u sin (t)

Solution steps

sin (t) u (t - 2 π)

= u sin (t) (t - 2 π)

Apply the distributive law:

a (b - c) = ab - a c

a = sin (t) u, b = t, c = 2 π

= sin (t) u t - sin (t) u \cdot 2 π

= t u sin (t) - 2 π u sin (t)

2 x - 1 \cdot (x - 1)

(x^{2} - 1) (e^{x})

(x + 1 + 2) (x + 1 - 2)

\frac{2 + x - x ^{2}}{( x - 1 ) ^{2}}

What is expand sin(t)u(t-2pi) ?
The solution to expand sin(t)u(t-2pi) is tusin(t)-2piusin(t)